3 years ago

If g(x)+xsin(g(x))= x^2 find g'(0) ...?

1 answer:

5 0

Differentiating implicity gives

g'(x) + xcos(g(x))(g'(x)) + sin(g(x)) = 2x

g'(x)[1 + xcos(g(x))] = 2x - sin(g(x))

g'(x) = [2x - sin(g(x))] / [1 + xcos(g(x))]

g'(0) = -sin(g(0))

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