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Evgesh-ka [11]
3 years ago
15

If g(x)+xsin(g(x))= x^2 find g'(0) ...?

Mathematics
1 answer:
Alexxx [7]3 years ago
5 0
Differentiating implicity gives 

g'(x) + xcos(g(x))(g'(x)) + sin(g(x)) = 2x 

g'(x)[1 + xcos(g(x))] = 2x - sin(g(x)) 

g'(x) = [2x - sin(g(x))] / [1 + xcos(g(x))] 

<span>g'(0) = -sin(g(0))


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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