Answer:
$3100 is invested at 9%
$4900 is invested at 11%
Step-by-step explanation:
Let's take "x" be the amount invested at 9%.
(x + 1800) is invested in another account at 11%.
The interest amount earned by the two accounts is $818.
Here we can use the simple interest formula and find the amount invested in each account.
Simple interest (I) = , where P- is the principal , N is the number of years and R is the interest rate.
Simple interest =
0.09x + 0.11(x+1800) = 818
Now we have to simplify and find the value of x .
Use the distributive property and simplify the second term.
0.09x + 0.11x + 198 = 818
0.2x + 198 = 818
0.2x =818 - 198
0.2x = 620
x = 620/0.2
x = 3100.
So $3100 is invested at 9%
x + 1800 = 3100 + 1800
= $4900
$4900 is invested at 11%
Hope this helped.
ANSWER:
Segment TS is a Chord
If AR = 14 , then QS = 14 ×2 = 28
∆ATS is an Isosceles Triangle
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Answer:
D
Step-by-step explanation:
Answer:
3.188
Step-by-step explanation:
Given that :
Sample data: 26.5, 28, 30.2, 29.6, 32.3, 24.7
Sample standard deviation (s) = 2.728
Mean (mu) = 25
Tstatistic formula :
(x - mu) / (s/sqrt(n))
n = sample size = 6 ; s = 2.728 ; mu = 25
Sample mean (x) = (26.5 + 28 + 30.2 + 29.6 + 32.3 + 24.7) / 6
Sample mean (x) = 171.3 / 6 = 28.55
Tstatistic = (28.55 - 25) / (2.728 / sqrt(6))
Tstatistic = 3.55 / 1.1137013
Tstatistic = 3.1875692