Answer:
The unit price at Price-Club is $0.2158 per ounce.
The unit price at Shop Mart is $0.2925 per ounce.
Step-by-step explanation:
Price Club:
12-ounce box of crackers for $2.59
So
12 ounces - $2.59
1 ounce - x



The unit price at Price-Club is $0.2158 per ounce.
Shop Mart:
1-pound box of crackers for $4.68.
1 pound is 16 ounces. So
16 ounces - $4.68
1 ounce - x



The unit price at Shop Mart is $0.2925 per ounce.
Answer:
x=8,9
Step-by-step explanation:
x^2-17x+72=0
(x-8)(x-9)=0
x=8,9
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
Answer:
♡ madeline here ♡
1+1=2 i'm so sorry i am late! ☆
have a great day! hope this helps.
- madeline/madi
✧・゚: *✧・゚:・゚✧*:・゚✧・゚
Step-by-step explanation: