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Ghella [55]
3 years ago
13

g You are riding a roller-coaster going around a vertical loop, on the inside of the loop. If the loop has a radius of 47.0 m, h

ow fast must the cart be moving in order for you to feel 2.5 times as heavy at the bottom of the loop
Mathematics
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Let the speed of the roller coaster at the bottom is v.

radius, r = 47 m

Let the mass is m and the force at the bottom is 2.5 times the weight.

F = 2.5 mg

So, the force is

F = mg + \frac{mv^{2}}{r}

2.5 mg= mg + \frac{mv^{2}}{r}

1.5g=\frac{v^{2}}{r}

v² = 1.5 gr

v² = 1.5 x 9.8 x 47

v = 26.3 m/s

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Rudiy27

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Answer:

  see attached

Step-by-step explanation:

I like to use a spreadsheet for repetitive calculations. The distances are computed from the distance formula:

  d = √((x2 -x1)^2 +(y2 -y1)^2)

The results are shown in the second attachment. The drawing in the first attachment has the lengths rounded to the nearest tenth.

7 0
2 years ago
R = sec(θ) − 2cos(θ), where -π/2 < θ < π/2
Alex

Answer:

  y = (x/(1-x))√(1-x²)

Step-by-step explanation:

The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:

  x = r·cos(θ)

  y = r·sin(θ)

  x² +y² = r²

__

  r = sec(θ) -2cos(θ)

  r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)

  r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²

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4 0
2 years ago
What si the Gcf of 28 42 and 56
vitfil [10]

Answer:

GCF=2

Step-by-step explanation:

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42-1,2,3,6,7

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4 0
3 years ago
Which of these values for p and a will cause the function f(x)=Pax to be an exponential growth function
vovikov84 [41]

The option are missing in the question. The options are :

A.  P = 2, a = 1

B.  $P=\frac{1}{2} ;  a =\frac{1}{3}$

C. $P=\frac{1}{2} ;  a =1$

D. P = 2, a = 3

Solution :

The given function is $f(x)= Pa^x$

So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.

When the four option being substituted in the function, we get

A). It is a constant function since $2(1^x)=2$

B). Here, the value of a is a fraction which is less than 1, so it is a decay function. $f(x)=\frac{1}{2}\left(\frac{1}{3}\right)^x$

C). It is a constant function since the value of a is 1.

D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

  $f(x)=2(3)^x$

Therefore, option (D). represents an exponential function.

4 0
2 years ago
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