Question

The height (in feet) of a rocket launched from the ground is given by the function f(t) = -16t2 160t. match each value of time elapsed (in seconds) after the rocket’s launch to the rocket's corresponding instantaneous velocity (in feet/second).

Answer 1

EachEach value of time elapsed (in seconds) corresponding instantaneous velocity (in feet/second) are:2s= 96, 3s = 64, 4s= 32, 5s = 0, 6s = -32, 7s = -64. 8s= -96, 9s= -128.

Velocity

Given equation:

f(t) = -16t² +160t

Velocity (v)=df(t)/dt

=-2×16t²+ 160t

=-32t+160

Hence:

-32t+160

1.     -32×(1) + 160 =    128ft/s

2.    -32×(2) + 160 =    96ft/s

3.    -32×(3) + 160 =    64ft/s

4.    -32×(4) + 160 =     32m/s

5.    -32×(5) + 160 =     0m/s

6.   -32×(6) + 160 =   -32m/s

7.    -32×(7) + 160 =    -64m/s

8.   -32×(8) + 160 =    -96m/s

9.    -32×(9) + 160 =   -128m/s

The pairs are;

2s= 96

3s = 64

4s= 32

5s = 0

6s = -32

7s = -64

8s= -96

9s= -128

Learn more about velocity here:brainly.com/question/4931057

#SPJ1