EachEach value of time elapsed (in seconds) corresponding instantaneous velocity (in feet/second) are:2s= 96, 3s = 64, 4s= 32, 5s = 0, 6s = -32, 7s = -64. 8s= -96, 9s= -128.
<h3>Velocity</h3>Given equation:
f(t) = -16t² +160t
Velocity (v)=df(t)/dt
=-2×16t²+ 160t
=-32t+160
Hence:
-32t+160
1. -32×(1) + 160 = 128ft/s
2. -32×(2) + 160 = 96ft/s
3. -32×(3) + 160 = 64ft/s
4. -32×(4) + 160 = 32m/s
5. -32×(5) + 160 = 0m/s
6. -32×(6) + 160 = -32m/s
7. -32×(7) + 160 = -64m/s
8. -32×(8) + 160 = -96m/s
9. -32×(9) + 160 = -128m/s
The pairs are;
2s= 96
3s = 64
4s= 32
5s = 0
6s = -32
7s = -64
8s= -96
9s= -128
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Given:
In triangle KLM, KL = 123 cm and measure of angle K is 35 degrees.
To find:
The length of the side KM to the nearest tenth of a centimeter.
Solution:
In a right angle triangle,
In the given right triangle KLM,
Multiply both sides by 123.
The measure of side KM is 100.8 cm.
Therefore, the correct option is (2).