Answer:
3(Y-2) +5Y =Y+22
3Y-6 +5Y=Y+22
3Y -6 +5Y-Y-22=0
3Y+5Y-Y-6-22=0
7Y-28=0
7Y=28
Y=28/7
Y=4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
After lunch the friends walked 6 3/4 miles before arriving at the end of the trail.
The trail is 14 1/8 miles long.
Question asked:
How long did the friends walk before lunch ?
Solution:
Let the friends walk before lunch in miles =
As total length of trail is given , we can conclude:
Total length of trail = The friends walk before lunch in miles + The friends walk after lunch in miles
Subtracting both side by
Taking LCM of 4 and 8 ,we get 8
Therefore, the friends walk before lunch is .
You should set up an X and Y table. Make time X and Distance Y. (the table is like a cross: on the left top put x and left top put y. Then under the line list the x and y numbers given in order.) Then find the "slope" which is y/x (rise over run) then you get the increase rate of 45 mph. The relation between them would be D=45t
x,z,y = 20,15,-33
i think thats it im sorry