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saw5 [17]
3 years ago
7

What is the answer for(y⁴)³

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0
The answer to the problem is y^12
Illusion [34]3 years ago
4 0
The answer is y^12

you multiply the 4 and 3 together

hope this helps
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If Cos 30° equals rad 3/2 then the sin 60° equals <br><br> a) 0<br> b) 1/2<br> c) rad 3/2<br> d) 1
vovangra [49]

Answer:

c) rad 3/2

Step-by-step explanation:

If Cos 30° equals rad 3/2 then the sin 60° equals rad 3/2.

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3 years ago
Leila went to see a baseball game. The game started at 11:39AM and ended at 3:15 PM. How long was the game?
stepan [7]

Answer:

3 hours and 21 miinutes

Step-by-step explanation:

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3 years ago
three sets of the sum of a number and four are added to the sum of seven times the same number and thirteen
almond37 [142]

The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

<em><u>Solution:</u></em>

Given the statement:

Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen

Let us first understand the given statement,

Let the number be "x"

" sum of a number and four" means x + 4

"Three sets of a sum of a number and four" translated to 3(x + 4)

"sum of seven times the same number and thirteen" means 7x + 13

<em><u>Thus the algebraic expression for given statement is:</u></em>

3(x+4)+(7x + 13)

<em><u>Using distributive property in above expression</u></em>

a(b+c) = ab + bc

Therefore,

3(x+4)+(7x + 13) = 3x + 12 + 7x + 13

<em><u>Combine the like terms</u></em>

3(x+4)+(7x + 13) = 10x+25

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

7 0
3 years ago
Help me with this!! Will mark Brainliest ❤️
Andrei [34K]

Answer:

Yes

Step-by-step explanation:

5 0
3 years ago
A caterer is planning a large dinner party for 1001 guests. Each table must seat an equal number of​ guests, more than 1 guest a
MArishka [77]

Answer:

The prime factorization of 1001 is 7*11*13, so with the constraint that the tables seat between 2 and 19 guests, we can use tables that seat either 7, 11, or 13 guests.

For tables that seat 7, the caterer would need 11*13 = 143 tables.

For tables that seat 11, the caterer would need 7*13 = 91 tables.

Step-by-step explanation:

5 0
3 years ago
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