Question

Solve the system of equations.

Answer 1

$\left\{\begin{array}{ccc}5x+3y=41\\3x-6y=9&|:2\end{array}\right\\\underline{+\left\{\begin{array}{ccc}5x+3y=41\\1.5x-3y=4.5\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ \ 6.5x=45.5\ \ \ \ \ |:6.5\\.\ \ \ \ \ x=7\\\text{put the value of x to the firdt equation}\\5(7)+3y=41\\35+3y=41\ \ \ |-35\\3y=6\ \ \ |:3\\y=2\\\\\text{Answer:}\ x=7,\ y=2$