Answer:
7 hours
Step-by-step explanation:
Step one:
given data
let the total charges be y and the number of hours be x
Company A charges
$60 reservation fee plus another $15 per hour.
so
y=60+15x----------1
Company B charges
$25 reservation fee plus another $20 per hour
y=25+20x------------2
Step two:
equate the 2 expressions above we have
60+15x=25+20x
collect like terms
60-25=20x-15x
35=5x
divide both sides by 5
x= 35/5
x= 7 hours
The differential equation that models the given situation will be dy/dt = K(N - y).
<h3>How to compute the equation?</h3>
Let y = number of individuals who have heard about the product.
Let N - y = this who haven't heard about the product.
From the given statement, the rate for change will be t = dy/dt. Therefore, the differential equation that models the given situation will be dy/dt = K(N - y).
Learn more about equations on:
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LiftA= u m/s ( upwards)
LiftB= -u m/s(downward)
Velocity A relative to B= V lift A- V lift B=8m/s
u-(-u)=8
u=4m/s
Lift A= 4 m/sec
Lift B= -4m/sec
For someone standing on first floor will be stationary W.r.t to the lift.
V lift A relative to Man= V liftA - V man= 4m/s
V lift B relative to Man= V lift B- V Man= -4 m/s
Answer:
-1772
Step-by-step explanation:
The nth term of an arithmetic sequence is expressed as;
Tn = a+(n-1)d
a is the first term
n is the number of terms
d is the common difference
From the sequence
a = 28
d = 8-28 = -12-8 = -20
n =91(since we are looking for the 91st term)
Substrate
T91 = 28+(91-1)(-20)
T91 = 28+90(-20)
T91 = 28-1800
T91 = -1772
Hence the 91st term is -1772
Answer:
- as written, c ≈ 0.000979 or c = 4
- alternate interpretation: c = 0
Step-by-step explanation:
<em>As written</em>, you have an equation that cannot be solved algebraically.
(32^2)c = 8^c
1024c = 8^c
1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero
A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.
___
If you mean ...
32^(2c) = 8^c
(2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2
2^(10c) = 2^(3c) . . . . . . . simplify
10c = 3c . . . . . . . . . . . . . .log base 2
7c = 0 . . . . . . . . . . . . . . . subtract 3c
c = 0 . . . . . . . . . . . . . . . . divide by 7
