The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
Changes in gas equals -5 times 6
After six hours the changes in gas were -30
Step-by-step explanation:
Answer:
Step-by-step explanation:
A(1,7); B(-3,-1); slope m =(-1-7)/-3-1) = -8/-4 = 2
Equation of a line AB is
((y-y1) = m(x-x1)
y - 7 = 2(x-1)
y - 7 = 2x-2
y = 2x + 5
Answer and Step-by-step explanation:
90ft = a
55ft = b
50ft = c
Plug into equation.

29.4° is the answer.
Answer:
Step-by-step explanation:
<u><em>Not congruent</em></u>
Better to say that there is not enough information to say, "Triangles are congruent"