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2 years ago

Write 98 as the product of prime factors in ascending order

Mathematics

2 answers:

Verizon [17]2 years ago

5 0

2*7^2? Is that the answer

umka2103 [35]2 years ago

4 0

to write 98 as a product of its prime factors we have to first find the prime factors of 98

prime factors are prime numbers by which the given number can be divided by.

98 we have to keep dividing it by prime numbers

98 is an even number so we can first divide by 2

98 / 2 = 49

49 is a multiple of 7 which too is a prime number so we can divide 49 by 7

49/7 = 7

7 can be divided again by 1

7/7 = 1

98 is divisible by 2 and 7

so 98 written as a product of prime factors is

98 = 2 x 7 x 7

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3 years ago

Stephen & Richard share a lottery win of £2950 in the ratio 2 : 3. Stephen then shares his part between himself, his wife &a

horsena [70]

Answer:

Stephen's wife got £354 more than his son.

Step-by-step explanation:

Given:

Amount of Lottery = £2950

Now Given:

Stephen & Richard share a lottery amount in the ratio 2 : 3

Let the common factor between them be 'x'.

So we can say that;

$2x+3x=2950\\\\5x = 2950$

Dividing both side by 5 we get;

$\frac{5x}{5}=\frac{2950}{5}\\\\x = 590$

So we can say that;

Stephen share would be = $2x =2\times 590 = \£1180$

Now Given:

Stephen then shares his part between himself, his wife & their son in the ratio 3 : 5 : 2.

Let the common factor between them be 'y'.

So we can say that;

$3y+5y+2y=1180\\\\10y=1180$

Dividing both side by 10 we get;

$\frac{10y}{10}=\frac{1180}{10}\\\\y=118$

So Stephen's wife share = $5y = 5\times 118= \£590$

And Stephen's son share = $2y=2\times118 =\£236$

Now we need to find how much more her wife got then her son.

To find how much more her wife got than her son we will subtract Stephen's son share from Stephen's wife share.

framing in equation form we get;

Amount more her wife got than her son = $590-236 = \£354$

Hence Stephen's wife got £354 more than his son.

3 0

3 years ago