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Sergio [31]
3 years ago
8

Steven, Linda, and Elliott check their lunch

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

Steven, Elliot, Linda

Step-by-step explanation:

-12<3<7

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2 years ago
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X2−10x+29=5
Irina18 [472]

Answer:

(x-6)(x-4) = 0

Step-by-step explanation:

Subtract 5 from both sides to make the equation equal to 0. You will get the equation x2-10x+24=0. Now think of two numbers that multiply to get 24 but add to get -10. These numbers are -6 and -4. The factors of x2 are x and x which multiply to get x2.  Now put two linear factors into parathesis to get (x-6)(x-4) = 0.

7 0
3 years ago
30x10-91x3-30 factorizar
Mrrafil [7]

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Step-by-step explanation:

4 0
3 years ago
15 = -4p + 7<br><br><br> solving equation
Ratling [72]

Answer:

p = -2

Step-by-step explanation:

15 = -4p + 7

4p + 15 = 7

4p + 15 - 15 = 7 - 15

4p = -8

4p/4 = -8/4

p = -2

8 0
3 years ago
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For which of the following equations are x = 5 and x = –5 both solutions?
Minchanka [31]
Short Answer B
Argument
A
A will give you x = +/- 5i 
x^2 + 25 = 0
x^2 = - 25       Take the square root.
sqrt(x^2) = +/- sqrt(-25)
x = +/- (5)i which is a complex number.


B
Is the answer
x^2 = 25
sqrt(x)^2 = sqrt(25)
x = +/- 5

C
Can't be factored just by looking at it. You can show that C is not true just by putting 5 into the equation
f(x) = x^2 + 10x - 25
f(5) = 25 + 10*5 - 25
f(5) = 50
C is not true.

D
D can be eliminated as C was
f(x) = x^2 - 5x - 25
f(5) = -25 ( l'll let you show this is not true). 5 is not a solution because it does not make f(x) = 0
6 0
3 years ago
Read 2 more answers
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