Question

A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces ...?

Answer 1

The solution to the problem is as follows:

W=Fd=mad=425*1.8*66 =50490 J

Therefore, it takes 50490 J of work the crane will do to accelerate the beam upward at 1.8 m/s^2.

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Answer 2

425 x 66 x 9.81 = 275170.5 J = 2.75 X 10 ^5 J = 275.17 kJ