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Stolb23 [73]
3 years ago
10

A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam acceler

ates upward at 1.8 m/s2? Neglect frictional forces ...?
Mathematics
2 answers:
Fiesta28 [93]3 years ago
6 0
<span>The solution to the problem is as follows:

W=Fd=mad=425*1.8*66 =50490 J

Therefore, it takes </span><span>50490 J of work the crane will do to accelerate the beam upward at 1.8 m/s^2.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
TRuthS2 years ago
0 0

425 x 66 x 9.81 = 275170.5 J = 2.75 X 10 ^5 J = 275.17 kJ

TRuthS
2 years ago
then, minus 425 x 1.8 x 66 = 224 680.5 J
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Answer:

Step-by-step explanation:

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    area of triangle =  1/2 × (y units) × (x units)       you need to count and insert

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area of triangle =  1/2 × (??? y units ) × (??? x units )    do the math yourself

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                                                                                       answers

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