Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
V ≈ 2144.70 
Step-by-step explanation:
Radius is going to be used instead of the diameter. Half of 16 is 8, and so that will be the value that shall be used.
V ≈ 2144.66
V ≈ 2144.70
To earn at least $3,200 in revenue, the ticket prices should be $10 or $40.
<h3>What is an
Equation</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Revenue = number of tickets sold * price per ticket = (400 - 8p)p
Revenue = 400p - 8p²
For no revenue:
400p - 64p² = 0
p = $0 or p = $50
For revenue of atleast 3200:
400p - 8p² = 3200
p = $10 or p = $40
To earn at least $3,200 in revenue, the ticket prices should be $10 or $40.
Find out more on Equation at: brainly.com/question/1214333
Answer:
scale factor in figure A and B is 3
6. 14/8=1.75
28/16=1.75
They are equal to each other
