Answer:
c) (26.295, 28.705)
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 27.5 - 1.205 = 26.295 mi/gallon
The upper end of the interval is the sample mean added to M. So it is 27.5 + 1.205 = 28.705 mi/gallon
So the correct answer is:
c) (26.295, 28.705)