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malfutka [58]
3 years ago
7

Simplify the following expression 2x^5+3x^3-5x^2+x^2+7x^5-3x^3-4

Mathematics
1 answer:
Travka [436]3 years ago
6 0

2x^5+3x^3-5x^2+x^2+7x+1+7x^5-3x^3-4\\\\=(2x^5+7x^5)+(3x^3-3x^3)+(-5x^2+x^2)+7x+(-4+1)\\\\=\boxed{9x^5-4x^2+7x-3}\to\boxed{C.}

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I feel 12 less than 4 times a number is 8, the number is 5. Write a different sentence where the unknown number is also 5.
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9 less than 3 times a number is 6

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Write the equation of the line shown in point slope form (1,2) (3,6)
Kipish [7]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (1, 2) and (3, 6). Substitute:

m=\dfrac{6-2}{3-1}=\dfrac{4}{2}=2\\\\\boxed{y-2=2(x-1)}

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3 years ago
How do u simlpify 6feet/8yards?
Julli [10]
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5 0
3 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
Wes measures the floor area of his rectangular living room to replace the carpet with tiles.The room is 12.4 feet long and 9.8 f
Zina [86]

Answer: 121.52 square feets

Step-by-step explanation:

The room has the shape of a rectangle and its dimensions are 12.4 feet long and 9.8 feet wide. This means that dimension of the carpet is also 12.4 feet long and 9.8 feet wide. To replace the rectangular carpet with tiles, the area of the tiles must be equal to the area of the carpet. The area of the carpet is determined by length × width.

Length of the room or carpet = 12.4 feets

Width of the room or carpet = 9.8 feets

The number of square feets of tiles that Wes will need

=12.4 ×9.8 = 121.52 square feets

7 0
3 years ago
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