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3 years ago

FInd the volume of the square pyramid shown round to the nearest tenth if necessary 11cm 11cm 15cm

Mathematics

2 answers:

k0ka [10]3 years ago

8 0

Volume = 1/3 * area of base * height

=1/3 * 11^2 * 15

= 605 cm^3 Answer

Inessa [10]3 years ago

7 0

So to find the volume of a square pyramid, the formula is 1/3B2h or Base squared times height divided by 3 because of the triangular pyramid. So the base is 11, the height is 15 so 11 squared is 121 and the height is 15, so 121 times 15.

121 x 15= 1,815.

Now we divide by 3 because of the formula, so 1,815 divided by 3 is...

1,815 / 3= 605 cm squared!

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!/8 pound of fertilizer covers 25 square feet of ground, how much fertilizer, in pounds, is needed to cover 1 square foot ground

suter [353]

Answer:

1/200 pounds

Step-by-step explanation:

Given ratio

1/8 pound ⇔ 25 square feet

To find

x ⇔ 1 square foot

Divide both sides by 25

1/8÷25 pounds ⇔ 25÷25 square feet
1/200 pounds ⇔ 1 square foot

3 0

3 years ago

Read 2 more answers

Can someone tell me what it is and explain it in an easy way, I'm kind of an idiot

lubasha [3.4K]

1/2 x 3/4
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3 years ago

Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.

statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that $p = \frac{231}{361} = 0.6399$

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095$

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

$E = -31*0.4095 + 21*0.5905 = -0.29$

The expected value of the proposition is of -0.29.

3 0

3 years ago

Translations, rotations, and reflections are rigid transformations. What can you conclude about the measures of sides and angles

attashe74 [19]

Answer:

After a translation, the measures of the sides and angles on any triangle would be the same since translation only involves changing the coordinates of the vertices of the triangle.

After a rotation, the measures of the sides and angles of a triangle would also be the same. Similar to translation, the proportion of the triangle is unchanged after a rotation.

After a reflection, the triangle's sides and angles would still be the same since reflection is a rigid transformation and the proportion of the sides and angles are not changed.

Step-by-step explanation:

Rigid transformations, i.e. translations, rotations, and reflections, preserve the side lengths and angles of any figure. Therefore, after undergoing a series of rigid transformations, the side lengths and angle measures of any triangle will be the same as the original triangle, generally speaking, in another position.

4 0

3 years ago

The diagonals of a quadrilateral are of lengths 6cm and 8cm. If the diagonals bisect each other at the right angles. Find the le

maks197457 [2]

Answer:

Each side is 5 cm

Step-by-step explanation:

What you are being told is that the figure is a rhombus. The two sides of a right triangle are 1/2 the size of the diagonals.

a = 3

b = 4

c = the side length of the rhombus.

a^2 + b^2 = c^2

3^2 + 4^2 = c^2

9 + 16 = c^2

25 = c^2

Take the square root of 25

sqrt(c)^2 = sqrt(25)

c = 5

5 0

3 years ago