All categories

2 years ago

The two lines y=2/5x+9 and y= -2/5x-9 are: a) parallel b) perpendicular c)neither

Mathematics

1 answer:

irakobra [83]2 years ago

8 0

Answer:

neither

Step-by-step explanation:

parallel lines have the same slope and different y-intercept

perpendicular lines have the reciprocal as slopes( 2/5 and 5/2)

as these slopes have neither the answer in NEITHER

You might be interested in

PLEASE help I will mark you as brainy

larisa86 [58]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

14) A solid metallic block measures 1.5m long, 0.4m wide and 0.25m high. The solid is made of

GREYUIT [131]

Answer:

<h3>The answer is </h3><h3 /><h3>1125 Kg</h3>

Step-by-step explanation:

To find the mass in kg we must first convert the density from g/cm³ to kg/m³

That's 7.5 g/cm³ = 7500kg/m³

Density = mass / volume

Volume of block = 1.5 × 0.4 × 0.25

= 0.15m³

mass = Density × volume

= 7500 × 0.15

Hope this helps you

7 0

2 years ago

Hiiiiiiiiii. plz help me and answer this correctly for brainliest and 50+ points

Angelina_Jolie [31]

its b because x+6 never changes

7 0

3 years ago

Read 2 more answers

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

6 0

3 years ago

I need help is this a función

labwork [276]

Answer

it is the 3rd one I believe sorry if you got it wrong thought

Step-by-step explanation:

I think you can find the explan on g00gle or on your notes if you write any

4 0

2 years ago