Answer:
No
Step-by-step explanation:
jan-44
feb-84
mar-72
apr-96
may-52
jun-26
mean=(44+84+72+96+52+26)/6=62.3<65
The answer is no
Answer:
if your number is 1000 there should be one decimal at the end so it should be 1000. Because 1000. And 1000 are the same thing
Step-by-step explanation:
This is a table with 6 lines.
In each line, the number in the first column is the 'x' value.
All you have to do on each line is ...
--- substitute the 'x' value in (100 + 23x), simplify it,
and write the result in the middle column
then
--- substitute the 'x' number in 90(1.2ˣ) , simplify it,
and write the result in the last column.
On the first line, x=0.
100 + 23x = 100 + 0 = 100. Write 100 in the middle column.
90(1.2ˣ) = 90(1) = 90. Write 90 in the last column.
Then go on to the second line, where x=1.
You'll make it.
Ay^2+2ay-3a
a(y^2+2y-3)
a(y-1)(y+3)
9514 1404 393
Answer:
KK KL KM KN KP LL LM LN LP MM MN MP NN NP PP
Step-by-step explanation:
Instead of starting with adjacent letters in the list, we start with the same letter. There are 15 possible pairs.
KK KL KM KN KP LL LM LN LP MM MN MP NN NP PP
__
<em>Additional comment</em>
We leave out pairs with letters previous, because you've said KL is the same as LK, and KL has already been listed. The problem with this list is that it misstates the probabilities of randomly obtaining a given pair. It is not 1/15, but is 2/25 for all but letter duplicates. For duplicates (KK), the probability is 1/25, not 1/15.
