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kumpel [21]
3 years ago
8

What is the factorization of 3x^2-8x+5

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

(x - 1)(3x - 5)

Step-by-step explanation:

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x-term.

product = 3 × 5 = 15 and sum = - 8

The factors are - 3 and - 5

use these factors to split the middle term

3x² - 3x - 5x + 5 ( factor the first/second and third/fourth terms )

= 3x(x - 1) - 5(x - 1) ( take out the common factor (x - 1) )

= (x - 1)(3x - 5)


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In rhombus ABCD, the diagonals AC and BDintersect at E. If AE=5 and BE=12, what is thelength of AB?
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Diagonals that bisect each other are perpendicular and form a right angle.

AEB is a right triangle.

We can apply the Pythagorean theorem:

c^2 = a^2+b^2

Where c is the hypotenuse (longest side) and a and b the other 2 legs.

Replacing:

AB^2 = AE^2+BE^2

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3 years ago
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3 years ago
Find the circumference of the circle.
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Step-by-step explanation:

Given

The radius of the circle = r = 5 in

We know that diameter is twice the radius.

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Using the formula to find the circumference of the circle

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