If f(x) = 6x - 5 and (x) = -x + 1 , what is the value of f(g(-3)).

On Halloween 4 friends each received 4⁄5 of a pound of candy. How much candy did they receive total?

Leokris [45]

Answer:

16/5 or 3 1/5

Step-by-step explanation:

Your equation would be 4/5*4 which equals 16/5

4 0

3 years ago

What is 4,000,000 + 700,000 + 20,000 + 9,000 + 600 + 60 + 2 in standard form?

Ivanshal [37]

Answer:

4729662

Step-by-step explanation:

5 0

3 years ago

Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim

andreev551 [17]

Answer:

$p_v =P(t_{74}$

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation

$\bar X=18.81$ represent the average lateral recumbency for the sample

$s=8.4$ represent the sample standard deviation

$n=75$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a left tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \geq 20$

Alternative hypothesis : $\mu < 20$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227$

The degrees of freedom are given by:

$df=n-1=75-1=74$

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

$p_v =P(t_{74}$

Conclusion

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0

3 years ago

What is the slope of the line that is perpendicular to the line that passes through (-2, 7) and (4, 9)? Type a numerical answer

kodGreya [7K]

Answer:

Therefore $m_{2}$ = -3.

Step-by-step explanation:

i) let us say the slope of the line passing through (-2,7) and (4,9) is $m_{1}$ .

ii) to find the slope of the line passing through two points ( $x_{1}$ , $y_{1}$ ) and ( $x_{2}$ , $y_{2}$ ) we use the formula m = $\dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }$ . Therefore we can say that $m_{1}$ = $\dfrac{9 - 7}{4 - (-2)}$ = $\dfrac{1}{3}$ .

iii) let us say the slope of the perpendicular line to the line passing through (-2,7) and (4,9) is $m_{2}$

iv) from the formula for the slopes of a line and the line perpendicular to it which is given by $m_{1}$ × $m_{2}$ = -1, therefore $m_{2}$ = -1 ÷ $m_{1}$ = -3. Therefore $m_{2}$ = -3

6 0

3 years ago

Darnell is trying to decide on the dimensions of his next painting. He wants to length to vary inversely with the width. The tab

alexandr1967 [171]

Answer:

D)

Step-by-step explanation:

We know that it cannot be C since z is not involved in this problem.

a) 3/20x

Try with 20 = x

3/440 ≠ 3

A is not the answer.

b) 60x

Try with 20 = x

1800 ≠ 3

B is not the answer.

c) 60/x

Try with 20 = x

3 = 3

Try with 15 = x

4 = 4

D is your answer.

Hope this helps. Have a nice day. Oh, and one more thing. Surprised to see I'm not stealing points?

8 0

3 years ago