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Eva8 [605]
3 years ago
12

If f(x) = 6x - 5 and (x) = -x + 1 , what is the value of f(g(-3)).

Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0

Answer:

19

Step-by-step explanation:

f(x) = 6x - 5

g (x) = -x + 1

f(g(-3))

g(-3) = - (-3) +1 = 3+1 = 4

f(g(-3) = f(4))

f(4)= 6(4) -5 = 24-5 = 19

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ale4655 [162]

t = 2/3. Multiply the numbers in the parentheses by -1. It becomes 9t + -3t + -3 = 1. Combine like terms to get 6t + -3 = 1. Add 3 to both sides to get 6t = 4. Divide both sides by 6. t = 2/3

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3 years ago
The formula s=√A4.828 can be used to approximate the side length s of a regular octagon with area A. A stop sign is shaped like
PtichkaEL [24]

Answer:742

Step-by-step explanation:

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3 years ago
CORRECT ANSWER GETS 95 POINTS AND BRAINLIEST
ollegr [7]

Answer:

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6 0
3 years ago
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Jaden is flying a kite and let’s off 275 feet of string. If the kite is 150 feet above ground and assuming the string is straigh
vivado [14]

Answer:

≈ 33°

Step-by-step explanation:

So, first, you can draw a visual. Refer to the image attached below:

Using this info, you can use trigonometric ratios. Recall that:

tangent = opposite side/adjacent side

sine = opposite side/ hypotenuse

cosine = adjacent side/hypotenuse

You can clearly see that you have an opposite side and a given hypotenuse. This means we'll be using sine.

So:

sinX = \frac{150}{275}

However, we're not trying to find sinX, we're trying to find X.

So we would have to use inverse sine, which would then be:

X = sin-1 (\frac{150}{275} )

Put this into your calculator, and:

X ≈ 33.05573115...

3 0
3 years ago
1.Give one number that makes the inequality x + 7 > 20 true
nata0808 [166]
1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.

Examples: 14+7 > 20, 30+7 > 20, 100+7 > 20

2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.

Examples: 3(8) < 25, 3(5) < 25, 3(0) < 25

3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)

To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.

4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)

To find this answer I did 300/16 and got 18.75. You must round to the higher whole <span>number. Rounding down to 18 boxes leaves you with 12 candies without a box.</span>
6 0
3 years ago
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