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saw5 [17]
3 years ago
5

The difference y less than 10

0less%20%5C%3A%20than%20%5C%3A%2010" id="TexFormula1" title="the \: difference \: \: y \: less \: than \: 10" alt="the \: difference \: \: y \: less \: than \: 10" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Art [367]3 years ago
3 0

Answer:

The difference is : 10 - y

Step-by-step explanation:

Let we donate the required difference by 'd'

Now, we need to find difference(d) in such a way that it is y units less than 10. So, Using concept of algebraic expressions :

A number which is less than another can be found by subtracting first number from the second number :

So, the required difference is given by : d = 10 - y

umka21 [38]3 years ago
3 0
10-y because it id the difference of y less than 10
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Let f:X → Y, where X and Y are the set of all real numbers, and x and h are real numbers.
Shkiper50 [21]

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a) f(x) = x^2

b) f(x) = x

c) any pair of numbers

Step-by-step explanation:

HI!

a)

an example of this kind of function is f(x) = x^2 because

f(x+h) = (x+h)^2 = x^2 + h^2 + 2 xh = f(x) + f(h) + 2xh

teherfore

f(x+h) ≠ f(x) + f(h)

other example is f(x) = x^n with n a whole number different than one

e.g.

f(x)=x^3

f(x+h) = (x+h)^3 = x^3 + h^3 + 3(x^2 h + x h^2) ≠ x^3 + h^3 = f(x) + f(h)

b)

f(x) = x is a function that actually behaves as indicated

f(x+h) = x + h = f(x) + f(h)

others examples of this kind of fucntion are given by multiplying x by any number:

f(x) = ax;    f(x+h) = a(x+h) = ax + ah = f(x) + f(h)

c)

Any pair of numbers will make f(x+h) = f(x) + f(h), as mentioned in the previous section

lest consider 10 and 5

f(10+5) = 2 *(10+5) = 2*15 = 30

f(10) = 2*10 = 20

f(5) = 2*5 = 10

f(10) + f(5) = 20+10 = 30 = f(10+5)

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3 years ago
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