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3 years ago

No links, ty <3

Mathematics

1 answer:

levacccp [35]3 years ago

4 0

Answer:

sAy yOu aRe mY bAkA

Step-by-step explanation:

ty for the points <3

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PLZZ HELP URGENT

Mashcka [7]

Answer:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1 7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7 7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14 7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3 7x - 1...subbing in 3

5(3) + 2(3) = 15 + 6 = 21 7(3) - 1 = 21 - 1 = 20

5x + 2x...subbing in 4 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28 7(4) - 1 = 28 - 1 = 27

5x + 2x...subbing in 5 7x - 1...subbing in 5

5(5) + 2(5) = 25 + 10 = 35 7(5) - 1 = 35 - 1 = 34

5x + 2x result values are 1 more then 7x - 1 result values

there are no values that will make the 2 expressions equal....

because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one

Step-by-step explanation:

5 0

3 years ago

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Which of the following graph is the solution -10<3x-4<8

satela [25.4K]

Answer:

( − 2 , 4 )

Step-by-step explanation:

There were no graphs listed in your question. So...

Convert the inequality to interval notation.

6 0

4 years ago

Ruden bought 6 new books for his collection, increasing his collection by 12%. How many books did he have before his purchase?

forsale [732]

Answer:

he had 44 books before he bought those 6

Step-by-step explanation:

If you multiply 6 times 2 it is 12, which means if you take away 12 from 100 that is 88. if you divided 88 by 2 (the same thing you did to the 6 to make it 12%) that would be 44.

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3 years ago

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

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3 years ago

-3=3x-3.solve for x?

Sunny_sXe [5.5K]

Add 3 on both sides of the equation

3x=0

divide 3 on both sides of the equation

x=0

7 0

3 years ago

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