All categories

3 years ago

No links, ty <3

Mathematics

1 answer:

levacccp [35]3 years ago

4 0

Answer:

sAy yOu aRe mY bAkA

Step-by-step explanation:

ty for the points <3

You might be interested in

I just passed my math test that i had no idea how to do :)

Wittaler [7]

As long as you believe in yourself, you can do anything.

7 0

2 years ago

Read 2 more answers

PLS HELP Solve for n. -3 + n = 8

Tamiku [17]

Answer:

-3 + 11 = 8

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Look at the Screenshot and ANSWER THE QUESTION

ad-work [718]

Answer:

Graph C is the answer.

Step-by-step explanation:

From the graphs attached,

Graph A

Given graph represents a cubic function.

Graph B

This graph represents a piecewise function.

Graph C

This graph represents an exponential function.

Graph D

Given graph represents a quadratic function.

Graph C is the answer.

6 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

Fabulous fitness charges a one time fee of $90 and an additional $25 per month wonder weights charges a one time fee of only $ 2

Aleksandr-060686 [28]

Answer:

9 months

Step-by-step explanation:

Given

Fabulous fitness charges a one-time fee of $90 and an additional $25 per month

let the number of months be x

and the total charges be y

y= 25x+90---------1

Wonder weights charges a one-time fee of only $ 27 dollars but charge an additional $32 each month

let the number of months be x

and the total charges be y

y= 32x+27------------2

Required

The value of x, that is the number of months

Step two:

Equating both equations we have

25x+90=32x+27

collect like terms

25x-32x=27-90

-7x=-63

7x=63

divide both sides by 7

x= 63/7

x= 9 months

6 0

2 years ago