All categories

2 years ago

A car traveled 180 miles at a constant rate. If the car traveled for 5 hours,

Mathematics

2 answers:

saul85 [17]2 years ago

4 0

Answer:

36 mph

Step-by-step explanation:

In this question, we are trying to find how many miles the car drives PER hour.

We know that the car traveled 180 miles, and within the travel it took the car 5 hours.

To find your answer, we would simply divide 180 by 5 to see how many miles she drove per hour.

Solve:

180/5 = 36

This means that the rate of travel of the car is 36 mph.

MakcuM [25]2 years ago

4 0

Answer : 36 mph.
180/5 = 36

You might be interested in

In a sample of 150 cars, 18 cars failed a safety inspection. The sampling method had a margin of error of 0.02

mestny [16]

Answer:

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

Step-by-step explanation:

Total number of cars = 150

Cars that failed the safety inspection = 18

The proportion is given by

p = 18/150

p = 0.12

p = 12%

The confidence interval is given by

p ± margin of error

Where margin of error is 0.02

0.12 ± 0.02

Lower limit = 0.12 - 0.02

Lower limit = 0.10

Lower limit = 10%

Upper limit = 0.12 + 0.02

Upper limit = 0.14

Upper limit = 14%

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

7 0

2 years ago

Y = 6x = 11 -2х – Зу = -7 Please show steps of solving

ahrayia [7]

3/4-3=43 Thsts the answer hopes it help

6 0

2 years ago

Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a

Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

X = a person has the disease

P = the test result is positive

N = the test result is negative

Given:

$P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10$

Compute the value of P (P|X) as follows:

$P(P|X)=1-P(P|X^{c})=1-0.15=0.85$

Compute the probability of a positive test result as follows:

$P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22$

Compute the probability of a person having the disease given that he/she was tested positive as follows:

$P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864$

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

3 0

2 years ago

At Freddy’s fro yo shop 25 percent of the 44 frozen yogurt flavors are sugar free how many frozen yogurt flavors are sugar free

daser333 [38]

25%of44=11 .so 11 frozen yogurt flavours are sugar free

6 0

1 year ago

Use the information to answer questions 8 and 9.

inessss [21]

Answer:

Step-by-step explanation:

the factors and prime factorization of 36 and 54. The biggest common factor number is the GCF number. So the greatest common factor 36 and 54 is 18.

8 0

3 years ago