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e-lub [12.9K]
3 years ago
12

Determine the end behavior for function ƒ(x) = –x(x – 8)(2 – x).

Mathematics
1 answer:
saveliy_v [14]3 years ago
4 0
It's a cubic with a positive x^3 coefficient. The general shape is "/".

It goes to -∞ for large negative x.
It goes to +∞ for large positive x.

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Can someone plz help me ASAP thxs
allsm [11]

Answer:

352

Step-by-step explanation:

8 x 6 x 8 = 384

384- (4 x 1 x 8)

384-32=352

6 0
3 years ago
What are the solutions to 3n-1 > 8 or 4n+ 3 ​
Mandarinka [93]

Answer:

n>3

Step-by-step explanation:

Step 1: Add 1 to both sides.

3n−1+1>8+1

3n>9

Step 2: Divide both sides by 3.

3n/3>9/3

n>3

3 0
3 years ago
Read 2 more answers
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
3 years ago
A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty
Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: \hat{p}=0.84

Significance level : \alpha= 1-0.98=0.02

Critical z-value : z_{\alpha/2}=2.33  (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}

i.e. \approx0.84\pm 0.085

i.e. (0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0
3 years ago
Costs 21.36 +1.17x=73
Ierofanga [76]

Answer:

what are we actually solving for?....

anyways I had a suggestion ion know if it's right or wrong....

<em>Isolate</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>by</em><em> </em><em>diving</em><em> </em><em>each</em><em> </em><em>side</em><em> </em><em>by</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>don't</em><em> </em><em>contain</em><em> </em><em>the</em><em> </em><em>vari</em><em>able</em><em>.</em>

<em>Therefore</em><em> </em><em>x</em><em>=</em><em>7</em><em>.</em><em>2</em>

8 0
4 years ago
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