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romanna [79]
2 years ago
9

Solve for x: 6 < 4x + 8 < 14

Mathematics
1 answer:
Lady_Fox [76]2 years ago
3 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \tt \dashrightarrow \:6 < 4x + 8 < 14

\qquad \tt \dashrightarrow \:6 - 8 < 4x  + 8 - 8 < 14 - 8

\qquad \tt \dashrightarrow \: - 2 < 4x < 6

\qquad \tt \dashrightarrow \: \dfrac{ - 2}{4}  <  \dfrac{4x}{4}  <  \dfrac{6}{4}

\qquad \tt \dashrightarrow \: \dfrac{ - 1}{2}  <  {x}{}  <  \dfrac{3}{2}

hope it helps ~

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If a person tosses a coin 23 times, how many ways can he get 11 heads
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Tossing a coin is a binomial experiment.

Now lets say there are 'n' repeated trials to get heads. Each of the trials can result in either a head or a tail.

All of these trials are independent since the result of one trial does not affect the result of the next trial.

Now, for 'n' repeated trials the total number of successes is given by

_{r}^{n}\textrm{C}

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In our case n=23 and r=11,

Substituting the values we get,

_{11}^{23}\textrm{C}=\frac{23!}{11!\times 12!}

\frac{23!}{11!\times 12!}=1352078

Therefore, there are 1352078 ways to get heads if a person tosses a coin 23 times.


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hjlf

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