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romanna [79]
2 years ago
9

Solve for x: 6 < 4x + 8 < 14

Mathematics
1 answer:
Lady_Fox [76]2 years ago
3 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \tt \dashrightarrow \:6 < 4x + 8 < 14

\qquad \tt \dashrightarrow \:6 - 8 < 4x  + 8 - 8 < 14 - 8

\qquad \tt \dashrightarrow \: - 2 < 4x < 6

\qquad \tt \dashrightarrow \: \dfrac{ - 2}{4}  <  \dfrac{4x}{4}  <  \dfrac{6}{4}

\qquad \tt \dashrightarrow \: \dfrac{ - 1}{2}  <  {x}{}  <  \dfrac{3}{2}

hope it helps ~

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