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Usimov [2.4K]
4 years ago
7

A motorboat travels 9 miles downstream (with the current) in 30 minutes. The return trip upstream (against the current) takes 90

minutes. Which system of equations can be used to find x, the speed of the boat in miles per hour, and y, the speed of the current in miles per hour? Recall the formula d = rt. 9 = 0.5(x – y) 9 = 1.5(x + y) 9 = 1.5(x – y) 9 = 0.5(x + y) 0.5 = 9(x – y) 1.5 = 9(x + y) 1.5 = 9(x – y) 0.5 = 9(x + y)

Mathematics
2 answers:
dalvyx [7]4 years ago
7 0

Answer:

This might help u........

Aleonysh [2.5K]4 years ago
7 0

Answer:

the answer is B

Step-by-step explanation:

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350 plus 10?
that equal or do tey want something more extreme
7 0
3 years ago
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Please solve and show all work thanks
mars1129 [50]

Answer:

  The smallest of the two consecutive integers is 10 or less.

Step-by-step explanation:

Let x represent the smallest of the even integers in the sequence.

Then the sum of two consecutive even integers is ...

  x + (x +2) = 2x +2

And half the sum of the next two consecutive even integers is ...

  (1/2)((x +4) + (x +6)) = x + 5

The relationship between these values is ...

  2x +2 ≤ 7 + (x +5)

Subtracting x+2 gives ...

  x ≤ 10

The least of the two consecutive even integers is at most 10.

5 0
3 years ago
What is the answer to 7x-(5x+9)+4​
Darina [25.2K]
7x -5x -9 + 4
= 2x - 5
8 0
3 years ago
I need help please and thank you
vivado [14]

Step-by-step explanation:

diameter i.e. d = 12ft

radius i.e r= 6ft

Area of the circle is given by,

\pi {r}^{2}  = 3.14  \times {(6)}^{2}

= 3.14 \times 36 = 113.04  \:  \: {ft}^{2}

8 0
4 years ago
The width of a rectangle is only 15% of its length. If the perimeter of the rectangle is 46, what is the length
sveta [45]

Answer:

20 units

Step-by-step explanation:

Let the length be x. According to the question,

  • Length = x
  • Width = 15% of the length

➝ Width = 15% of the length

➝ Width = 15/100x

➝ Width = 3/20x

We have the perimeter of the rectangle that is 46 units.

\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {\dfrac{46}{2}=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23 \times 20 = 23x} \\

\longrightarrow \sf {460= 23x} \\

\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\

\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>rectang</u><u>le</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>units</u><u>.</u>

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3 years ago
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