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natulia [17]
3 years ago
12

What is the answer to 7x-(5x+9)+4​

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0
7x -5x -9 + 4
= 2x - 5
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F(x) - 3x -9; g(x) = x -4 what is the value of (g o f)(x)
Ratling [72]
-3x-13
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4 years ago
This is super important for my grade guys can you please let me know the answer
nignag [31]

Answer: the last one

Step-by-step explanation:

3 0
3 years ago
Find all the missing elements:
Evgesh-ka [11]

Answer:

a=10.8; c=4.3

Step-by-step explanation:

The sum of all the angles in a triangle is 180 degrees.

Two of the angles are given as 40 deg and 120 deg.

Subtract the measures of both from the sum to get the last angle:

180-40-120=20; ∠C=20°

Using Law of Sines: \frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}

\frac{a}{sin120}=\frac{8}{sin40}; a=\frac{8*sin120}{sin40}; a=10.77837084

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8 0
3 years ago
What is ∑n=14[100(−4)n−1] equal to? Enter your answer in the box.
larisa [96]

Answer:

-5100

Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
A company manufacturing oil seals wants to establish X and R control charts on the process. There are 25 preliminary samples of
alisha [4.7K]

Answer:

A ) i) X control chart : upper limit = 50.475, lower limit = 49.825

    ii) R control chart : upper limit =  1.191, lower limit = 0

Step-by-step explanation:

A) Finding the control limits

grand sample mean = 1253.75 / 25 = 50.15

mean range = 14.08 / 25 = 0.5632

Based on  X control CHART

The upper control limit ( UCL ) =

grand sample mean + A2* mean range ) = 50.15 + 0.577(0.5632) = 50.475

The lower control limit (LCL)=

grand sample mean - A2 *  mean range = 50.15 - 0.577(0.5632) = 49.825

Based on  R control charts

The upper limit = D4 * mean range = 2.114 * 0.5632 = 1.191

The lower control limit = D3 * mean range = 0 * 0.5632 = 0  

B) estimate the process mean and standard deviation

estimated process mean = 50.15 = grand sample mean

standard deviation = mean range / d2  = 0.5632 / 2.326 = 0.2421

note d2 is obtained from control table

6 0
3 years ago
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