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lozanna [386]
3 years ago
15

There were 13,531 new products introduced last year. If 87% of the products introduced last year failed to reach their business

objectives, find the number of products that were successful.
Mathematics
1 answer:
kvasek [131]3 years ago
7 0
I'm assuming that since 87% failed, that would the remaining 13% was a success.  If that assumption is correct, than we simply have to take:

.13 * 13531 = 1759.03 products were successful.
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enyata [817]

Answer:

9^8

Step-by-step explanation:

9²•9⁶​ = 9^(2+6) = 9^8

3 0
2 years ago
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Luke made cookies he used 1/2 of a cup of flour and 2/5 of cup of sugar. How much more flour than sugar did Luke use
VLD [36.1K]

Answer:

1/10

Step-by-step explanation:

2/5 a cup of sugar

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-Convert to 10ths:

4/10 of sugar, and 5/10 of flour.

Luke used 1/10 more flour than sugar.

8 0
2 years ago
PLEASE HELP WILL MARK BRAINLIEST
77julia77 [94]

Answer:

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6 0
1 year ago
A card is randomly chosen from the cards in the image. Find the probability of choosing the cards with either Q or R on them.
Afina-wow [57]

The probability of choosing cards either Q or R when a card is drawn from a deck of 8 cards is 0.25.

Given that a card is randomly chosen from 8 cards shown in figure.

We have to calculate the probability of choosing either Q or R when a card is drawn from those 8 cards.

Probability means calculating the likeliness of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative.

Number of cards=8

Number of repeated cards=0

Number of cards showing Q and R =1 each.

Probability of getting Q or R is P(X=Q)+P(X=R)

= 1/8+1/8

=2/8

=1/4

=0.25

Hence the probability of getting either P or Q when a card is drawn from 8 cards is 0.25.

Learn more about probability at brainly.com/question/24756209

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6 0
1 year ago
If SAT scores are normally distributed with a mean of 1518 and a standard deviation of 325, find the probability that a randomly
aliya0001 [1]
Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575

Z = (X - x_bar)/sigma

Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18

From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714

P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316

The correct answer is C.
3 0
3 years ago
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