The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
Answer:
<h3>#5</h3>
<u>Given vertices:</u>
These have same x-coordinate, so when connected form a vertical segment.
<u>The length of the segment is:</u>
The area of the rectangle is 72 square units, so the horizontal segment has the length of:
<u>Possible location of the remaining vertices (to the left from the given):</u>
and
<h3>#6</h3>
<u>Similarly to previous exercise:</u>
- (5, -8) and (5, 4) given with the area of 48 square units
<u>The distance between the given vertices:</u>
<u>The other side length is:</u>
<u>Possible location of the other vertices (to the right from the given):</u>
and
Answer:
206
Step-by-step explanation:
70% of 294
70/100 × 294/1
205.8
round it off to 206
One possible equation for this quadratic would be
y=(x-4)²-1. This is vertex form: y=a(x-h)²+k, where (h, k) is the vertex.
However, this is not the only possible equation. There could be multiple values for a, in front of the parentheses, that we don't know about from the information we are given.
We can also write this equation in standard form (y=ax²+bx+c). First write the squared binomial as the product of two binomials:
y=(x-4)(x-4)-1
Multiply the binomials:
y=x*x-4*x-4*x-4(-4)-1
= x²-4x-4x--16-1
= x²-8x+16-1
= x²-8x+15
Again, this would change depending on what the value of a is in the functoin.