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AfilCa [17]
3 years ago
9

Which of the following expressions is equivalent to 3x + 3x + 5 + 5?

Mathematics
2 answers:
Aleks [24]3 years ago
6 0

Answer:  The correct option is

(B) 2(3x+5).

Step-by-step explanation:  We are given to select the expression that is equivalent to the following expression :

E=3x+3x+5+5~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following property :

az+bz=(a+b)z.

From expression (i), we get

E\\\\=3x+3x+5+5\\\\=(3+3)x+10\\\\=6x+10\\\\=2\times3x+2\times5\\\\=2(3x+5).

Thus, the required equivalent expression is 2(3x+5).

Option (B) is CORRECT.

Kipish [7]3 years ago
4 0
Remember
ab+ac=a(b+c0

3x+3x+5+5
2(3x)+2(5)
2(3x+5)

2nd option
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7.32

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1000 = 7320

0.006

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100 = 0.6

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For example, if you had 0.6 multiplied by 100, you would move 2 decimal places to the right because 100 has two zeros.

3 0
3 years ago
How do you find the square root of a number?
MariettaO [177]

Answer:

multiply a number  by a number

Step-by-step explanation:

such as 8 times 8=64

which means the square root of 64 is 8

3 times 3=9

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6 0
2 years ago
1) Anna and Jason have summer jobs stuffing envelopes for two different companies. Anna earns $20 for every 400 envelopes she fi
AleksAgata [21]

Answer:

The answer is below

Step-by-step explanation:

A) i)

For Anna initially, she has $0 from making 0 envelopes. After making 400 envelopes she has $20. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (400, 20). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{20-0}{400-0}(x-0)\\\\y=\frac{1}{20} x

The table is:

x:   200     400       600     800     1000

y:    10        20          30        40       50

ii)

For Jason initially, he has $0 from making 0 envelopes. For every 250 envelopes he has $10. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{10-0}{250-0}(x-0)\\\\y=\frac{1}{25} x

The table is:

x:   200     400       600     800     1000

y:    8         16           24        32       40

The graph is plotted using geogebra online graphing

b) From the table above we can see that Anna makes more stuffing than Jason.

c) Anna has a savings of $100. Hence this can be represented by the points (0, 100) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-100=\frac{20-0}{400-100}(x-0)\\\\y=\frac{1}{15} x+100

We can see from the graph that there is a y intercept at 100. That is the earnings starts from 100.

The equation of a line is given as y = mx + b, where m is the slope and b is the y intercept (initial value)

For the first graph, the slope is 1/20 and the initial value is 0 while for the second graph the slope is 1/15 and the initial value is 100

D) The line pass through (10, 10) and (100, 40), hence:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-10=\frac{40-10}{100-10}(x-10)\\\\y-10=\frac{1}{3} (x-10)\\\\y=\frac{1}{3}x+\frac{20}{3}

3 0
3 years ago
How do i solve this as an inequality?<br>a. 2x+6 &lt;14<br><br>please send a step by step!! :)​
Y_Kistochka [10]

Answer:

2x+6<14

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6 0
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