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2 years ago

What is the product 823 times 43?

Mathematics

1 answer:

vredina [299]2 years ago

3 0

823 × 43 = 35389

anything to ask please pm me

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Step-by-step explanation:

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2 years ago

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2 years ago

What is the area of a semicircle whose perimeter is 72cm

Nuetrik [128]

Answer:

A = 307.9 sq/cm

Step-by-step explanation:

Find the radius of the semi-circle

diameter + half the circumference = 72 cm

2r + pi*r = 72

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r = 72%2F%28%282%2Bpi%29%29

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2 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20-%20%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%20%20%5Csqrt%7B%20%7B6%7D

strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

${2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\ \\ {2}^{x} - \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\ \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\ \\ {( {2}^{x} )}^{2} = {(\sqrt{ {6}^{x} })}^{2} \\ \\ {2}^{2x} = {6}^{x} \\ \\ {2}^{2x} = {(2 \times 3)}^{x} \\ \\ {2}^{2x} = {2 ^{x} \times 3}^{x} \\ \\ \frac{ {2}^{2x} }{ {2}^{x} } = 3^{x} \\ \\ {2}^{2x - x} = {3}^{x} \\ \\ {2}^{x} = {3}^{x} \\ \\ \frac{ {2}^{x} }{ {3}^{x} } = 1 \\ \\ \bigg( \frac{2}{3} \bigg)^{x} = 1 \\ \\ \implies \: x = 0 \\ \\ \because \: for \: x = 0 \\ \\ \bigg( \frac{2}{3} \bigg)^{0} = 1$

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2 years ago

Find the distance between the two points in simplest radical form.<br> (-1,9) and (4, -3)

jolli1 [7]

Answer:

GIVEN BY POINTS :-

( -1, 9) , ( 4 , -3)

Here ,

$\bullet \: \: x _{1} = - 1 \\ \bullet \: \: x _{2} = 4 \\ \bullet \: \: y _{1} = 9 \\ \bullet \: \: y _{2} = - 3 \\$

Using Distance formula :

$= > \sf d = \sqrt{( {x _{2} - x _{1}) }^{2} + {( {y _{2} - y _{1}) }^{2} } } \\ \\ = > \sf d = \sqrt{ ({ 4 + 1)}^{2} + { ( - 3 - 9)}^{2} } \\ \\ = > \sf d = \sqrt{ {5}^{2} + {( - 12)}^{2} } \\ \\ = > \sf d = \sqrt{25 + 144} \\ \\ = > \sf d = \sqrt{169} \\ \\ = > \boxed{ \sf{ d = 13\:units }}\\$

8 0

2 years ago