The answer to this would have to be the number 15 my good sir
The correct answer for the question is y=x
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
12 A . my guess would be to divide 2175 by 18 which would give you 120.83
Answer:
a=5
Step-by-step explanation:
a^2+b^2=c^2
c^2-b^2=a^2
13^2-12^2=a^2
169-144=a^2
25=a^2
5=a