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11111nata11111 [884]
3 years ago
11

In ABC the measure of angle a is 2X +3 the measure of angle B is 4X +2 and the measure of angle C is 2X-1 what are the measures

of the angles
Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
Angle A is 2x + 3
Angle B is 4x + 2
Angle C is 2x - 1

The three angles add up to 180
So:
2x + 3 + 4x + 2 + 2x - 1 = 180
Combine terms
8x +  4 = 180
Subtract 4
8x = 176
x = 22

Now we solve for the angles:
Angle A is 2(22) + 3 = 44 + 3 = 47
Angle B is 4(22) + 2 = 88 + 2 = 90
Angle C is 2(22) - 1 = 44 - 1 = 43

Quick check: 47 + 90 + 43 = 180
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Simplify 12,176 divided by 24
Harrizon [31]
12,176/24 = 1522/3 or 507 1/3
6 0
3 years ago
Factor using the trinomial<br> 10.<br> X2 + 13x + 12
Rudik [331]

Answer:

Factoring the trinomial: x^2+13x+12 we get the factors \mathbf{(x+1)(x+12)}

Step-by-step explanation:

We need to factor the trinomial: x^2+13x+12

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)

So, Factoring the trinomial: x^2+13x+12 we get the factors \mathbf{(x+1)(x+12)}

8 0
3 years ago
2sin 2x =1 ( 0 &lt; x 2π )
yuradex [85]

Answer:

17pie/12

Step-by-step explanation:

im sorry i don't have the pie sign

5 0
2 years ago
What is the area of a regular pentagon with a side of 7.2 and an apothem of 7
timofeeve [1]
The area of a regular polygon<span> is given by the formula which is expressed as:

</span>area = (½)(apothem<span>)(perimeter)
</span>
We calculate as follows:

area = (½)(7<span>)(7.2 x 5)
</span>area = 126 square units

Hope this answers the question.
5 0
3 years ago
No clue on this need help please
maria [59]
It would be 10x5 + 3x8= 74 
5 0
3 years ago
Read 2 more answers
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