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2 years ago

Help on 39 please ASAP !!!!!!!!!

Mathematics

2 answers:

artcher [175]2 years ago

8 0

6545742
Untis= 2
Ten= 4
Hundred= 7
Thousand= 5
Ten Thousand= 4
Hundred Thousand= 5
Million= 6

bonufazy [111]2 years ago

6 0

39.) 6 is in the millions place 5 is in the hundreds thousands place 4 is in the ten thousands place 5 is in the thousands place 7 is in the hundreds 4 is in the tenths and 2 is in the ones place

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Perform the indicated operation.(3/a+2) + (4/a-5)

kipiarov [429]

Answer:

$\frac{7(a-1)}{(a+2)(a-5)}$

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

$\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}$

Thus, the solution is 7(a -1) / (a+2)(a-5)

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2 years ago

Hurrry i need help nowwwwwwwwwwwwwwwww

nikklg [1K]

Answer: A y=4x^2+1

Step-by-step explanation:According to slope A is the answer

3 0

2 years ago

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A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

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2 years ago

Mikel is trying to save for college expenses. He has a job, but can only afford to put $20 per month aside. He has 4 years until

nadezda [96]

Answer:

960

20 times 12 moths to get 240 then multiply that by 4 years and get 960 .

Step-by-step explanation:

sorry if wrong ]

have a good day /night

may i pleae have a branlliest .

20 x 12=240 x 4 =960

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2 years ago

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Please help me with this. an explanation would be great as well

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

test the constant 1/2 + (1/2)*(-3) = -2/2 = -1

6 0

2 years ago

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