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3 years ago

Write a number sentence to compare 7.17 and 7.170

1 answer:

5 0

Both of these values are the same, so the number sentence would state:

7.17 = 7.170

You can place any number of zeros to the very end on the right side (when there is a decimal point) without changing the value of the number.

7.1700000 = 7.17 also

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Choice 1: Angela and Kellie went to lunch. Their bill before tax was $20.00. Tax is 8%. How much tax should

Zolol [24]

Answer:

$1.60

Step-by-step explanation:

Amount of tax paid = percentage of tax to be paid x bill before tax

0.08 x $20 = $1.60

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2 years ago

A square with a side length of 5 inches has a area of 25 in<br><br> true or false

Goryan [66]

Answer:

TRUE

Step-by-step explanation:

5 x 5 = 25 in²

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2 years ago

What is the value of 3 in 640.31? Choose ALL the correct answers

grigory [225]

Answer:

3/10 and 0.3

Step-by-step explanation:

Hope this helps! Pls give brainliest!

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1 year ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$