It is necessary to declare the function as a member of the class that overloads the ->c operator for the class.
<h3>What does C's -> operator mean?</h3>
- In C/C++, the Arrow operator makes it possible to access items in unions and structures.
- It is used in conjunction with a pointer variable pointing to a union or structure.
- As demonstrated below, the arrow operator is created by utilizing a negative sign and the greater than symbol.
- (Pointer name)->(Variable Name) is the syntax.
- To access members of a class, structure, or union using a pointer, use the -> (arrow) operator.
- A member of the object to which the pointer points is designated by a postfix expression, a -> (arrow) operator, followed by a potential qualified identifier or a pseudo-destructor name.
Therefore the correct answer is, c. ->
The complete question is:
The function that overloads the ____ operator for a class must be declared as a member of the class.
a. ::
b. *
c. ->
d. +
To learn more about -> operator, refer to:
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Explanation:
heyy
everyone come here for truth and dare
vzg-hqvy-wdn
Answer:
A: Backstage view > Account Settings
Explanation:
Answer: 443
Explanation:
Port 443 will need to be enabled for secure transactions to go through because it is the default port for HTTPS which is the transfer protocol for secure communication.
This way your credit card transactions will be encrypted to ensure protection from those who would seek to steal your data and your money.
Answer:
=IF(D3>50; E3; F3) AND =IF(A1>60;"Pass";"Fail")
Explanation:
An IF structure is built following this pattern:
IF(TEST;IFTRUE;IFFALSE)
These are the only options in the given drop-down menus what comply with this pattern. All others are not following this pattern.
The computer will do the test and if the result is true will apply the IFTRUE value, otherwise will apply the IFFALSE value.
