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AlexFokin [52]
3 years ago
8

Simplify numbers 6 7 8 9 10 11 and 12 please

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0
6)6x^2y^5
8) 4×5×6x
9)6×1×6
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Which equation describes the graph? (In the photo)
maw [93]

Answer:

C. The slope is 3 and the y-intercept is -3

3 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
Someone please help me with #2
mario62 [17]

<em>Good luck, you'll need it :)</em>

6 0
3 years ago
What is the range of this piecewise function
White raven [17]

Answer as a compound inequality: -4 \le y < 2

Answer in interval notation:  [-4, 2)

=============================================

Explanation:

The range is the set of all possible y outputs of a function. When dealing with a graph like this, we just look at the highest and lowest points to determine which y values are possible.

The lowest point occurs when y = -4. We include this value. So far we have y \ge -4 which is the same as -4 \le y

The upper ceiling for the y value is y = 2. We can't actually reach this value because of the open hole at (-3,2). So we say that y < 2

Combine -4 \le y and y < 2 to get the compound inequality -4 \le y < 2

This says y is between -4 and 2, including -4 but excluding 2.

To convert this to interval notation, we write [-4, 2) where the square bracket says to include the endpoint and the curved parenthesis says to exclude the endpoint.

6 0
2 years ago
Susan is writing a linear equation for the cost of her cell phone plan. In the first month, she talks for 52 minutes and is char
Alex787 [66]
Assuming that the cost per minute is the same for both months and the plan fee is the same, you can use y=mx+b for this

y is the cost of the phone plan, x is the cost per minute and b is the start cost.

so    19.41=25x+b for the first month
and  45.65=380x+b for the second month

solve both for b you get:
19.41-25x=b and 45.65-380x=b.  from this we get
19.41-25x=45.65-380x

solve for x

328x=26.24 and x=0.08

this means the cost per minute is 0.08c/min (answer A)

rewrite the equation to calculate b, and where this time, the x is the number of minutes talked.

y=0.08x+b and plug in one of the two months

45.65=0.08 * 380 + b

Solve for b and b is 15.25

so the final equation is

y=0.08x+15.25  (answer B)
5 0
3 years ago
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