All categories

3 years ago

What is the end behavior of the following Polynomial ? P(x)=-3x^4+3x-2 *

Mathematics

1 answer:

dangina [55]3 years ago

7 0

Answer:

up, down

Step-by-step explanation:

$p(x) = - 3 {x}^{4} + 3x - 2$

It is an even-degree polynomial. Therefore, the start of domain is the opposite the end of domain.

Meaning if the graph starts by decreasing, the graph will end by increasing.

Because the coefficient of highest degree is in negative. Therefore, the graph starts from negative infinity, increasing. The graph will end in positive infinity but decreasing.

Therefore, the answer is first choice.

You might be interested in

The average dog's running speed is about 20 miles per hour. If there are 5,280 feet in a mile, approximately how many feet can t

Nataly [62]

Answer:

B. 29

Step-by-step explanation:

Multiply your original speed by the amount of feet in a mile (5230) then divide by 3600.

3 0

3 years ago

What is the slope of this question

Otrada [13]

The slope would be 2

6 0

3 years ago

A town has accumulated 3 inches of snow, and the snow depth is increasing by 4 inches every

maxonik [38]

3 hours. I think. X represents the # of hours and they equal the same after exactly 3 hours.

8 0

3 years ago

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

3 years ago

Given the information below, write the conclusion in context. 1. H0 : The proportion of defective batteries = 0.02 2. HA : The p

Marizza181 [45]

Answer:

$z = -1.23$

And we can calculate the p value with the following probability taking in count the alternative hypothesis:

$p_v = P(z$

And for this case using a significance level of $\alpha=0.05 ,0.1$ we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true proportion is less than 0.02