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Strike441 [17]
3 years ago
5

10% of the students in a school like the color purple. 162 students don't like the color purple. How many students are in the sc

hool?
Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

There are 180 students at the school

Step-by-step explanation:

If 10% of the students like the color purple, then 100-10 = 90% do not like the color purple.

Students * percentage that do not like = students that do not like

students * 90% = 162

Change to decimal form

students *.90 = 162

Divide each side by .90

students *.90/.90 = 162/.90

students = 180

There are 180 students at the school

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Please help me........
kati45 [8]

Answer:

x = 54

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-12(x + 4) + 14x = 60

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -12:                              -12x - 48 + 14x = 60
  2. Combine like terms:                   2x - 48 = 60
  3. Add 48 to both sides:                 2x = 108
  4. Divide 2 on both sides:              x = 54
7 0
3 years ago
Read 2 more answers
The table shows the relationship between the number that fit into given number of boxes from a bakery . What is the missing valu
ki77a [65]

Answer:

The missing value should be 48 because between the two numbers of each group. They are multplied by 6

Step-by-step explanation:

Hope this Helped!

7 0
3 years ago
Read 2 more answers
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
John left his house in Irvine at 8:35 am to drive to a meeting in Los Angeles, 45 miles away. He arrived at the meeting at 9:50.
Vsevolod [243]

Answer:

b is the correct answer. I'm 95% positive

Step-by-step explanation:

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4 years ago
What side of the image corresponds to BC ?<br> http://prntscr.com/kvxwsm
coldgirl [10]
I’m pretty sure the answer is xy
8 0
3 years ago
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