The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:
93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x
Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y
Hope this helps!
A) The perimeter is the length around the rectangle, so it would be 2 + 5 + 2 + 5 = 14m
The area is 2m * 5m = 10m^2
b/c) You have to draw a rectangle with a perimeter of 14m, and an area that ISN'T 10m^2. You could draw a 3m by 4m rectangle which would have a perimeter of 14m and an area of 12m^2.
Answer:
thanks !
Step-by-step explanation:
You need to use the distance formula
so the distance between points (5,-2) and (-3,8) is
which won't simplify so it stays as is
