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Ilia_Sergeevich [38]

3 years ago

15

Bradbury scar caught 35 fish with his net 20 percent of the fish had to be thrown back into the sea because they were too small

how many fish did Bradbury throw back to sea

1 answer:

Lerok [7]3 years ago

6 0

7 fish were thrown back

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Find the 8th term of the geometric sequence 3, 9, 27, ...

miv72 [106K]

Answer:

8th term- 6,561

Step-by-step explanation:

Each term in the sequence is being multiplied by 3. For example, 3x3=9 and 9x3=27. Now, we need to continue multiplying numbers, so we can list them all here, still starting with 3.

1&2) 3x3=9

3) 9x3=27

4) 27x3=81

5) 81x3=243

6) 243x3=729

7) 729x3=2,187

8) 2,187x3=6,561

The 8th term of the geometric sequence is 6,561.

Hope this helps and have a great day! ^^

3 0

3 years ago

What’s the slope?<br> a line has the given equation y=-3x-10

spayn [35]

Answer: -3

Step by Step Explanation: This type of equation is called slope-intercept form, y=mx+b; the slope is m, so the slope is -3

5 0

3 years ago

Read 2 more answers

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

HELP!!! this is graded and no links plzzzzz!!!!!

vampirchik [111]

Answer:

88cm^2

Step-by-step explanation:

Area of the rectangle: base x height

Area of parallelogram: base x height

Area of the shaded part: area of rectangle -area of parallelogram:

12x10-4x8=120-32=88

5 0

3 years ago

PLEASE help no scam or ill report

dezoksy [38]

Answer:

These opposite angles are called Vertical Angles.

5 0

3 years ago