Answer:
2/3
Use the rise over run formula and then simplify
Answer:
The coach should start recruiting players with weight 269.55 pounds or more.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 225 pounds
Standard Deviation, σ = 43 pounds
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.15
Calculation the value from standard normal z table, we have,

Thus, the coach should start recruiting players with weight 269.55 pounds or more.
Answer:
a) Fx=-5N Fy=-5*sqrt(3) N b) Fx= 5*sqrt(3) N Fy=-5N
c) Fx=-5*sqrt(2) N Fy=-5*sqrt(2) N
Step-by-step explanation:
The arrow's F ( weight) component on axle x is Fx= F*sinA and on axle y is
Fy=F*cosA
a) The x component and y component both are opposite directed to axle x and axle y accordingly. So both components are negative.
So Fx = - 10*sin(30)= -5 N Fy= -10*cos(30)= -10*sqrt(3)/2= -5*sqrt (3) N
b) Now the x component is co directed to axle x , and y component is opposite directed to axle y.
So x component is positive and y components is negative
So Fx = 10*sin(60)= 5*sqrt(3) N Fy= -10*cos(60)= -10*1/2= -5 N
c)The x component and y component both are opposite directed to axle x and axle y accordingly. So both components are negative.
So Fx = - 10*sin(45)= -5*sqrt(2) N
Fy= -10*cos(45)= -10*sqrt(2)/2= -5*sqrt (2) N
Given:
Total number of coins (Quarters and dimes) = 60
Total amount = $12.45
To find:
The number of quarters and dimes.
Solution:
Let x be the number of quarters and y be the number of dimes.
We know that,
1 quarter = 0.25 dollar
1 dime = 0.10 dollar
Total coins:
...(i)
Total amount:
...(ii)
From (i), we get
...(iii)
Putting this value in (ii), we get




Divide both sides by 0.15.


Putting x=43 in (iii), we get


So, the number of quarters is 43 and the number of dimes is 17.
Therefore, the correct option is b.