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Julli [10]
3 years ago
10

I NEED HELP URGENT PLOT THE POINT!!!!

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0
-3/4 would be the line directly to the right of -1

11/4 would be the line directly to the left of 3
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Ishaan is 3times as old as Christopher and is also 14 years older than Christopher.
adoni [48]
Ishann is 21 years old.
8 0
3 years ago
What is the slope of the line shown below?
GaryK [48]

Answer:

2/3

Use the rise over run formula and then simplify

3 0
3 years ago
Read 2 more answers
A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0
4 years ago
Hi, can someone help me on this. I'm stuck --
CaHeK987 [17]

Answer:

a) Fx=-5N  Fy=-5*sqrt(3) N   b) Fx= 5*sqrt(3) N    Fy=-5N

c) Fx=-5*sqrt(2) N    Fy=-5*sqrt(2)   N

Step-by-step explanation:

The arrow's F ( weight) component on axle x  is Fx= F*sinA  and on axle y is

Fy=F*cosA

a) The x component and y component both are opposite directed to axle x and axle y accordingly.  So both components are negative.

So Fx = - 10*sin(30)= -5 N      Fy= -10*cos(30)= -10*sqrt(3)/2= -5*sqrt (3) N

b) Now the x component  is co directed to axle x , and y component is opposite directed to axle y.

So x component is positive and y components is negative

So Fx = 10*sin(60)= 5*sqrt(3) N       Fy= -10*cos(60)= -10*1/2= -5 N

c)The x component and y component both are opposite directed to axle x and axle y accordingly.  So both components are negative.

So Fx = - 10*sin(45)= -5*sqrt(2)  N    

 Fy= -10*cos(45)= -10*sqrt(2)/2= -5*sqrt (2) N

8 0
4 years ago
Jo jo has a total amount of $12.45 in quarters and dimes in his pocket. he has a total of 60 coins. how many quarters and dimes
baherus [9]

Given:

Total number of coins (Quarters and dimes) = 60

Total amount = $12.45

To find:

The number of quarters and dimes.

Solution:

Let x be the number of quarters and y be the number of dimes.

We know that,

1 quarter = 0.25 dollar

1 dime = 0.10 dollar

Total coins: x+y=60               ...(i)

Total amount: 0.25x+0.10y=12.45             ...(ii)

From (i), we get

y=60-x          ...(iii)

Putting this value in (ii), we get

0.25x+0.10(60-x)=12.45

0.25x+6-0.10x=12.45

0.25x-0.10x=12.45-6

0.15x=6.45

Divide both sides by 0.15.

x=\dfrac{6.45}{0.15}

x=43

Putting x=43 in (iii), we get

y=60-43

y=17

So, the number of quarters is 43 and the number of dimes is 17.

Therefore, the correct option is b.

8 0
3 years ago
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