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maxonik [38]
3 years ago
8

24÷4 4×4 What is the meaning of the unknown factor and quotient

Mathematics
1 answer:
Lorico [155]3 years ago
6 0
I dont know the meannig but i can tell you the answer, the first one is 6, and the second one is 16.
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What is 2*2^4 written as a single power?
S_A_V [24]

Step-by-step explanation:

2^1*2^4

2^1+4

2^5

when two same bases are multiplied their powers are added

7 0
3 years ago
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Can someone help please
Over [174]

Answer:

She is wrong. Only expression A and, expression C are equal.

Plz thank and rate brainliest.


8 0
4 years ago
Please Help Me With These Problems!!
galben [10]

The area painted red on one of the front wheels on DeMarius’ car will be 80.42 inches².

<h3>How to calculate the area?</h3>

From the information given, the The front wheels on DeMarius’ car are divided into sectors of equal area and the radius of each wheel is 8 inches. The area will be:

= 2/5 × πr²

= 0.4 × 3.14 × 8²

= 80.42 inches²

The radius, in feet, of a rear wheel on the car will be:

r1(2π) = r2(2π)

8(2π) = r2(8/5)(2π)

16 = r2(8/5)

r = 5/8 × 16

r = 10 inches

r = (5/6) feet

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brainly.com/question/25292087

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4 0
2 years ago
Can someone help me solve 7-12 plsss
Pavel [41]

Answer:-5

Step-by-step explanation:

3 0
3 years ago
The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra
kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

p-50 = \dfrac{50-52}{4000-3800}(x - 4000)

p-50 = \dfrac{-2}{200}(x - 4000)

p-50 = \dfrac{-x}{100}+ 40

p = \dfrac{-x}{100}+ 90

R(x) = x . p

R(x) = x (\dfrac{-x}{100}+ 90)

R(x) = \dfrac{-x^2}{100}+ 90x)

\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))

\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)

at \dfrac{d}{dx}(R(x)) = 0

\dfrac{-2x}{100}= -90

x = 4500

\dfrac{d^2}{d^2x}(R(x)) = -ve

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

p = \dfrac{-4500}{100}+ 90

p = $45

6 0
4 years ago
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