
<u>Step-by-step explanation:</u>
We have ,
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
⇒
×
×2
⇒ 
⇒
⇒
⇒
Its called an Scalene triangle
To find the answer, you need to round to the nearest tens. Round 142 to 140 and 1 68 to 160. You know that 1+1=2, and 6+4=10, so 200+100=300 pages read.
B the answer is B - hope this helps you out
Answer:
I get z = +1.8
x= 79
m= 73;s= 4;z= (x-m)/s= 1.5
hope it helps you