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kati45 [8]
3 years ago
12

The bottom of Ignacio’s desktop is 74.5 cm from the floor. Ignacio sits in his adjustable chair, and the top of his legs are 49.

3 cm from the floor. Each clockwise rotation of the knob on the chair raises Ignacio’s legs by 4.8 cm. Write an inequality to determine the number of clockwise rotations, r , Ignacio could make with the knob without his legs touching the desk.
Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
3 0

Answer: Ignacio can make 5 clockwise rotations.  

Step-by-step explanation: Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:

4.8r + 49.3 < 74.5  where 'r' is equal to the number of rotations

The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch.  Now, solve for 'r':

Subtract 49.3 from both sides:  4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2

Divide 4.8 from both sides:  4.8r/4.8 < 25.2/4.8 or  r < 5.25

Since the number of rotations must be less than 5.25, he can make 5 complete rotations.  

Simora [160]3 years ago
3 0

Answer:

5 rotations

Step-by-step explanation:

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Digiron [165]

Answer: 1211.6585 years

<u>Step-by-step explanation:</u>

The equation for exponential growth is: P=P_oe^{kt}

  • P: final population
  • P₀: initial population
  • k: rate of decay (or growth)
  • t: time

Use the half life information to find k:

\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}

Next, input the information (65% decayed = 35% remaining) and the k-value to find your answer.

.35P_o=P_oe^{-0.000867t}\\\\\\.35=e^{-0.000867t}\\\\\\ln(.35)=-0.000867t\\\\\\\dfrac{ln(.35)}{-0.000867}=t\\\\\\\large\boxed{1211.6585=t}

5 0
3 years ago
An object is moving in a straight line. It initially travelz at a speed on 9 meters per second, and speeds up at a constant rate
Crank

Answer:13 meters per second

Step-by-step explanation:

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Find the value of x. if your answer is not an interger, leave it in simplest radical form. The diagram is not drawn to scale. PL
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Just do pythagorean theorem. The answer is the square root of 75
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The present age of father is thrice as old as the age of daughter 5 years ago. If 5 years hence ,the age of father will be twice
pav-90 [236]

Answer:

<em>Hence the daughter's present age is 15 years</em>

<em>The fathers present age is 35 years</em>

<em></em>

Step-by-step explanation:

Let the present age of daughter be x

Let the present age of father be y

5 years ago;

Daughter's age = x - 5

Fathers age = y - 5

If the present age of father is thrice as old as the age of daughter 5 years ago, then;

y - 5 = 3(x-5)

y - 5 = 3x-15

y = 3x - 10 .... 1

In 5 years time;

Daughters age = x + 5

Fathers age = y + 5

If the age of father will be twice the age of his daughter in 5 years time then;

y+5 = 2(x+5)

y+5 = 2x + 10

y = 2x + 5 .....2

Equate 1 and 2;

3x - 10 = 2x + 5

3x - 2x = 5 + 10

x = 15

Since y = 2x + 5

y = 2(15) + 5

y = 35

<em>Hence the daughter's present age is 15 years</em>

<em>The fathers present age is 35 years</em>

<em></em>

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A bag contains 5 red marbles, 3 blue marbles, 7 yellow marbles, and 2 green marbles. Which ratio can be used to compare the yell
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Answer:

7:3

Step-by-step explanation:

The number of yellow marbles: the number of blue marbles

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3 years ago
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