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likoan [24]
3 years ago
6

Which calculation can be used to find the value of q in the equation q3 = 64?

Mathematics
2 answers:
Reptile [31]3 years ago
7 0
Q equals the cubed root of 64
Alchen [17]3 years ago
5 0
U could go on sacratic
You might be interested in
(sqrt3-sqrt3i)^4
Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}

(-1+sqrt3i)^12 = (-1 + √3i)¹²

|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt 3-i)^6 = (√3 - i)⁶

|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2

(sqrt2-i)^6 = (√2 - i)⁶

|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

Learn more about complex numbers here: brainly.com/question/10662770

#SPJ1

3 0
2 years ago
The product of six and a number is 66 find the number
Allushta [10]

Answer:

11

Step-by-step explanation:

If you add 11 6 times, you will get 66 or if you multiply 11 times 66 you will get 66.

3 0
3 years ago
If 10 centimeters equal 1 decimeter and it takes 8dm of shipping paper to wrap a large package. How many cm of paper would be ne
motikmotik
The answer would be 80cm

All you have to do is multiply 10×8 to get the answer
8 0
3 years ago
-3x - 8 + 6x = 7 wat is the answer
Aliun [14]
3x-8+6x=7
9x-8=7
9x=15
x=9/15
x=3/5

7 0
3 years ago
Read 2 more answers
Marisha walks 8 miles in 5 days. If she walks at the same rate, how far
stiv31 [10]

Answer:

56 miles

Step-by-step explanation:

6 0
3 years ago
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