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Crank
3 years ago
7

Can y’all help me with this and you’ll get 20 points

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
The answers to your page the whole book is online with answer key
You might be interested in
Plz Help
soldier1979 [14.2K]

the answer is B)

we can check by multiply them

8 0
3 years ago
Read 2 more answers
These both go together
Airida [17]

a) We know that the probability Jane will win is 0.2, and draws is 0.3, which leaves the probability of her losing to be 0.5 (1 - 0.2 - 0.3 = 0.5).

I'll begin by filling in for the first game:

win = 0.2, draw = 0.3, lose = 0.5

Next, we'll fill in for if she wins, draws, or loses the second game. The probabilities would be the same as the first game for the second game.

Win (0.2): win = 0.2, draw = 0.3, lose = 0.5

Draw (0.3): win = 0.2, draw = 0.3, lose = 0.5

Lose (0.5): win = 0.2, draw = 0.3, lose = 0.5

b) To find the probability that Jane will win both games, we need to multiply the probability of Jane winning the first game by the probability of her winning the second game.

0.2 x 0.2 = 0.04

Hope this helps! :)

6 0
3 years ago
The values shown represent the y-values that correspond to x-values from x = 1 through x = 5.
rjkz [21]
The answer is B because every number is adding up to 6
7 0
2 years ago
Find the percent of change. Round to the nearest tenth if necessary: 25 is increased by 80%
AleksAgata [21]

Answer:

45

Step-by-step explanation: Find what 80% of 25 is, you can do this by dividing 25 by 100. Then multiply the output by 80. Add that output to 25 and you should get an answer of 45.

6 0
2 years ago
(7 x6 )+(8x8)-5 gives the number of slicess were sold witch describe a part of this expression what's the sum
Afina-wow [57]

Answer:

"101" seems to the appropriate response. The further explanation is provided below.

Step-by-step explanation:

The given expression is:

⇒ (7\times 6 )+(8\times 8)-5

On solving the brackets, we get

⇒ 42+64-5

On applying addition, we get

⇒ 106-5

On applying subtraction, we get

⇒ 101

3 0
2 years ago
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