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miskamm [114]
3 years ago
13

Write the point-slope form of the equation of the line that passes through the origin and has a slope of 2. Include your work in

your final answer.
Mathematics
1 answer:
mestny [16]3 years ago
6 0
Y-0= 2(x-0) is point slope and ur answer
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Evaluate limit:<br> lim x approaches 0 e^(5x)-1-5x/x^2
rosijanka [135]
Lim as x approches 0 of (e^(5x) - 1 - 5x)/x^2 = lim as x approaches 0 of (5e^(5x) - 5)/2x = lim as x approaches 0 of 25e^(5x)/2 = 25/2 = 12.5
8 0
2 years ago
Intentionally writing a check on an account with insufficient funds should not be done. True Fals
Ede4ka [16]
False.

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6 0
3 years ago
I need help asap!! please!!
andre [41]
Wouldnt it be a dot on the line right in between 75 and 76 pointing towards the left? im not sure 
4 0
3 years ago
Read 2 more answers
NEED HELP ,,,,,,, HELP IF U CAN ASAP
kramer

Answer:

$24.84

Step-by-step explanation:

i did the work lol

give brainliest please

8 0
3 years ago
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Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
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