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NikAS [45]
3 years ago
13

Ind the amount of social security deducted from the check: $835 biweekly.

Mathematics
2 answers:
Tcecarenko [31]3 years ago
5 0
4.) Tax = 0.025 x 679 = $16.98

5.) Tax = 0.0175 x $43,210 = $756.18

6.) Tax = 0.03 x $314 = $9.42
belka [17]3 years ago
3 0

Answer:

$18.13

Step-by-step explanation:

For question #2 to find the amount of Social Security tax deducted from the given pay period you would need to multiple to the number by 0.0765.

Sooo, multiply .0765 * 237 = 18.13 to get your WEEKLY DEDUCTABLE!!!

Do the same for question #1

0.0765 * (x) = monthly

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(x - 6)(x - 2) the answer to the question

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Number 5 but if u can do number 6 that would be great ✋
mamaluj [8]

Answer:

5: 45 miles

6: y=20x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the following shows the factors of 5x^2+17x+6
ElenaW [278]

<span><span>(5x+2)</span><span>(x+3)</span></span>

Explanation:

Find factors of <span>5and 6</span> whose products ADD to 17

It might take a bit of trial and error to find the correct combination of factors.

<span><span>........</span>5 and 6</span>
<span><span>.......</span>↓ ↓</span>
<span><span>........</span>5 2 →1×2=2</span>
<span><span>........</span>1 3 →5×3=<span>15<span>−−</span></span></span>
<span><span>...............................................</span><span>17</span></span>

6 0
3 years ago
Read 2 more answers
The _______________ separates the region of rejection from the region of non rejection.
Alekssandra [29.7K]

Answer:

Critical Value

Step-by-step explanation:

The critical value separates the region of rejection from the region of non rejection.

We define critical values as:

  • Critical value helps us to give the decision rule for the rejection or acceptance of null hypothesis.
  • Critical value separates the acceptance region from the rejection region.
  • These are referred to as cut-off values that define regions where the test statistic is unlikely to lie.
  • The critical value depends on the kind of test being performed and the significance level.

6 0
3 years ago
The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran
VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, X = "Comprehensive strength of concrete". We have information that X is normally distributed with a mean of 2500 psi and a standard deviation of  50 psi (or a variance of 2500 psi). In other words, X \sim N(2500, 2500).

We want to know the probability of the mean of X or \bar{X} that falls in the interval [2499;2510]. From inference theory we know that :

\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)

Now we can find the probability as follows:

P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )

Where Z \sim N(0,1), then:

P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798

8 0
3 years ago
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