Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
sry if my answer is wrong but I think it is the square root of nine
Answer:
A. The perimeter of the original figure is multiplied by 3 ,and the area is multiplied by 9.
(9=3²)
it is a rule in the dilation course:
<span> add</span><span> up the two equivalent fractions </span>
<span>Add the two equivalent fractions</span><span> which now have a common denominator</span>
<span>Combine the numerators together, put the sum or difference</span><span> over the common denominator then reduce to lowest terms if possible. tell me if this helped you.</span>
X equals 1 and 2. When you put 1 into f(x) you get 2 and when you put 1 into g(x) you get 1 as well. The same for 2...but not the same for 3.
