The period will be the length for one cycle of the function.
answer: 10
Answer:
First term (a) =8
Common difference (d)= t2-t1
=12-8
=4
Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}
= 31/2{2×8+(31-1)4}
=31/2{16+(30×4)
=31/2(16+120)
=31/2×126
=31×63
Step-by-step explanation:
Similarly use 19 as (n) for the 19th term
Answer:
No
Step-by-step explanation:
Since they have the same denominator, you can compare the numerator. Since 2<3, then 2/6 < 3/6.
Answer:
6x^2(5x^4 +3)
Step-by-step explanation:
The greatest common factor of 18 = 3·6 and 30 = 5·6 is 6.
The greatest common factor of x^2 and x^6 is x^2.
Factoring 6x^2 from both terms, we get ...
... 18x^2 +30x^6 = 6x^2(3 +5x^4)
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<em>Comment on the question</em>
Since this answer is not among the answer choices, I suggest you ask your teacher to demonstrate how this problem is worked.
It appears as though the answers go with the problem 18x^9 +30x^6. Maybe there's a typo somewhere. For that problem, the best choice is the 2nd answer.
Answer:
A common mistake is doing x2-x1/y2-y1 instead of the correct slope formula which is y2-y1/x2-x1
Step-by-step explanation:
