Help im starving... jk help ,me with maTH

Mathematics

1 answer:

Step2247 [10]3 years ago

6 0

I'm not helping you bc of your pfp.

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Okay, so I'm a little bit upset at the moment. This morning I decided to make a brainly plus account with the yearly subscriptio

Nostrana [21]

Step-by-step explanation:

Wow that's sad sir..

Hope it gets better ;-;

8 0

2 years ago

I need help pls !!!!!!

swat32

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Trigonometry.

here, we use the Linear pair property of the adjacent angles.

We know that, all the adjacent angles in a linear pair add to get 180°

so we get as,

=> (n+6) +90°+(2n+3) =180°

=> (n+6) +(2n+3) =180-90

=> 3n+9 = 90

=> 3n= 90-9

=> 3n = 81

hence, n = 81/3

=> n = 27°

thus the value of n is 27° .

4 0

3 years ago

Can someone proove it to me<br> thank you for your help

Dovator [93]

$\sin(2x + x) = \sin(2x) \cos(x) + \\ \cos(2x) \sin(x) = 2 \sin(x) { \cos(x) }^{2} \\ + \sin(x) { \cos(x) }^{2} - { \sin(x) }^{3} = \\ 3 \sin(x) { \cos(x) }^{2} - { \sin(x) }^{3} = \\ 3 \sin(x) - 3 { \sin(x) }^{3} - { \sin(x) }^{3} = \\ 3 \sin(x) - 4 { \sin(x) }^{3}$

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3 years ago

Match each label to the correct location.

Nina [5.8K]

Match each label to the correct location.

5 0

3 years ago

. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.