All categories

3 years ago

A standard shower drain

Mathematics

1 answer:

Hunter-Best [27]3 years ago

3 0

Answer:

see the explanation

Step-by-step explanation:

The given rate is

$480\ \frac{gal}{h}$

Create three different rates, that are all equivalent to this rate

First rate

1,440 gallons in 3 hours

Find the units rate

Divide the total volume by the total time

$\frac{1,440}{3}=480\ \frac{gal}{h}$

Second rate

960 gallons in 120 minutes

Find the units rate

Divide the total volume by the total time

Convert minutes to hours

$120 \ min=2\ h$

$\frac{960}{2}=480\ \frac{gal}{h}$

Third rate

720 gallons in 1.5 hours

Find the units rate

Divide the total volume by the total time

$\frac{720}{1.5}=480\ \frac{gal}{h}$

Convert gal/h to gal/min

Remember that

$1\ h=60\ min$

$480\ \frac{gal}{h}=480/60=8\ \frac{gal}{min}$

You might be interested in

Any kind of clue please need help on this

Nikolay [14]

Similar polygons are made through scaling either by stretching or squeezing the sides all by a common ratio. Here, the size changes. Congruent polygons are made by shifting or reflecting their position. Here, the size does not change.

Choice A has a dilution (or squeezing) and a translation (shifting). That makes similar polygons.

Choice B has a rotation. Nope.

Choice C has a shifting and a reflection. Nope.

Choice D has a rotation and shifting. Nope.

Thus choice A is best.

7 0

3 years ago

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per in

TiliK225 [7]

Answer:

The population growth rate is 59 squirrels per year.

Step-by-step explanation:

Given:

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per individual per year and the population size is 275.

Now, to find the population growth rate.

Carrying capacity ( $K$ ) = 350.

Maximum rate ( $r_{max}$ ) = 1.0 per individual per year.

Population size ( $N$ ) = 275.

Now, to get the population growth rate we put formula:

$\frac{dN}{dT}= r_{max}\frac{K-N}{K}N$

$\frac{dN}{dT}=1.0\times \frac{350-275}{350}\times 275\\\\\frac{dN}{dT}=1.0\times \frac{75}{350}\times 275\\\\\frac{dN}{dT}=1.0\times 0.214\times 275\\\\\frac{dN}{dT}=58.85.$